(5x+6)(3x^2-4x+1)=0

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Solution for (5x+6)(3x^2-4x+1)=0 equation: 


Simplifying
(5x + 6)(3x2 + -4x + 1) = 0

Reorder the terms:
(6 + 5x)(3x2 + -4x + 1) = 0

Reorder the terms:
(6 + 5x)(1 + -4x + 3x2) = 0

Multiply (6 + 5x) * (1 + -4x + 3x2)
(6(1 + -4x + 3x2) + 5x * (1 + -4x + 3x2)) = 0
((1 * 6 + -4x * 6 + 3x2 * 6) + 5x * (1 + -4x + 3x2)) = 0
((6 + -24x + 18x2) + 5x * (1 + -4x + 3x2)) = 0
(6 + -24x + 18x2 + (1 * 5x + -4x * 5x + 3x2 * 5x)) = 0
(6 + -24x + 18x2 + (5x + -20x2 + 15x3)) = 0

Reorder the terms:
(6 + -24x + 5x + 18x2 + -20x2 + 15x3) = 0

Combine like terms: -24x + 5x = -19x
(6 + -19x + 18x2 + -20x2 + 15x3) = 0

Combine like terms: 18x2 + -20x2 = -2x2
(6 + -19x + -2x2 + 15x3) = 0

Solving
6 + -19x + -2x2 + 15x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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